6x+2x-3+12(2+10x)+16+2=0

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Solution for 6x+2x-3+12(2+10x)+16+2=0 equation: 



6x+2x-3+12(2+10x)+16+2=0

We add all the numbers together, and all the variables

6x+2x+12(10x+2)-3+16+2=0

We add all the numbers together, and all the variables

8x+12(10x+2)+15=0

We multiply parentheses

8x+120x+24+15=0

We add all the numbers together, and all the variables

128x+39=0

We move all terms containing x to the left, all other terms to the right

128x=-39

x=-39/128

x=-39/128

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