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6x+3(2x+4)=2x-3(2x-9)
We move all terms to the left:
6x+3(2x+4)-(2x-3(2x-9))=0
We multiply parentheses
6x+6x-(2x-3(2x-9))+12=0
We calculate terms in parentheses: -(2x-3(2x-9)), so:We add all the numbers together, and all the variables
2x-3(2x-9)
We multiply parentheses
2x-6x+27
We add all the numbers together, and all the variables
-4x+27
Back to the equation:
-(-4x+27)
12x-(-4x+27)+12=0
We get rid of parentheses
12x+4x-27+12=0
We add all the numbers together, and all the variables
16x-15=0
We move all terms containing x to the left, all other terms to the right
16x=15
x=15/16
x=15/16
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