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6x+3(2x-10)=102
We move all terms to the left:
6x+3(2x-10)-(102)=0
We multiply parentheses
6x+6x-30-102=0
We add all the numbers together, and all the variables
12x-132=0
We move all terms containing x to the left, all other terms to the right
12x=132
x=132/12
x=11
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