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6x+3(5x-4)=12(2x+5
We move all terms to the left:
6x+3(5x-4)-(12(2x+5)=0
We multiply parentheses
6x+15x-(12(2x+5)-12=0
We add all the numbers together, and all the variables
21x-(12(2x+5)-12=0
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