6x+3(x-1)=2(x+3)

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Solution for 6x+3(x-1)=2(x+3) equation: 



6x+3(x-1)=2(x+3)

We move all terms to the left:

6x+3(x-1)-(2(x+3))=0

We multiply parentheses

6x+3x-(2(x+3))-3=0



We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

9x-(2x+6)-3=0

We get rid of parentheses

9x-2x-6-3=0

We add all the numbers together, and all the variables

7x-9=0

We move all terms containing x to the left, all other terms to the right

7x=9

x=9/7

x=1+2/7

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