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6x+3(x-5)=12
We move all terms to the left:
6x+3(x-5)-(12)=0
We multiply parentheses
6x+3x-15-12=0
We add all the numbers together, and all the variables
9x-27=0
We move all terms containing x to the left, all other terms to the right
9x=27
x=27/9
x=3
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