6x+3-(3x-4)=x-4-(x+1)

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Solution for 6x+3-(3x-4)=x-4-(x+1) equation: 



6x+3-(3x-4)=x-4-(x+1)

We move all terms to the left:

6x+3-(3x-4)-(x-4-(x+1))=0

We get rid of parentheses

6x-3x-(x-4-(x+1))+4+3=0



We calculate terms in parentheses: -(x-4-(x+1)), so:

x-4-(x+1)

determiningTheFunctionDomain
x-(x+1)-4

We get rid of parentheses

x-x-1-4

We add all the numbers together, and all the variables

-5

Back to the equation:

-(-5)



We add all the numbers together, and all the variables

3x+12=0

We move all terms containing x to the left, all other terms to the right

3x=-12

x=-12/3

x=-4

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