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6x+3-2x-2=2(2x+4)
We move all terms to the left:
6x+3-2x-2-(2(2x+4))=0
We add all the numbers together, and all the variables
4x-(2(2x+4))+1=0
We calculate terms in parentheses: -(2(2x+4)), so:We get rid of parentheses
2(2x+4)
We multiply parentheses
4x+8
Back to the equation:
-(4x+8)
4x-4x-8+1=0
We add all the numbers together, and all the variables
-7!=0
There is no solution for this equation
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