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6x+3/2x+90=360
We move all terms to the left:
6x+3/2x+90-(360)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
6x+3/2x-270=0
We multiply all the terms by the denominator
6x*2x-270*2x+3=0
Wy multiply elements
12x^2-540x+3=0
a = 12; b = -540; c = +3;
Δ = b2-4ac
Δ = -5402-4·12·3
Δ = 291456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{291456}=\sqrt{576*506}=\sqrt{576}*\sqrt{506}=24\sqrt{506}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-540)-24\sqrt{506}}{2*12}=\frac{540-24\sqrt{506}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-540)+24\sqrt{506}}{2*12}=\frac{540+24\sqrt{506}}{24} $
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