6x+3/7x+1=2

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Solution for 6x+3/7x+1=2 equation:



6x+3/7x+1=2
We move all terms to the left:
6x+3/7x+1-(2)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
We add all the numbers together, and all the variables
6x+3/7x-1=0
We multiply all the terms by the denominator
6x*7x-1*7x+3=0
Wy multiply elements
42x^2-7x+3=0
a = 42; b = -7; c = +3;
Δ = b2-4ac
Δ = -72-4·42·3
Δ = -455
Delta is less than zero, so there is no solution for the equation

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