6x+3/7x+4=2

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Solution for 6x+3/7x+4=2 equation: 



6x+3/7x+4=2

We move all terms to the left:

6x+3/7x+4-(2)=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



We add all the numbers together, and all the variables

6x+3/7x+2=0

We multiply all the terms by the denominator


6x*7x+2*7x+3=0

Wy multiply elements

42x^2+14x+3=0

a = 42; b = 14; c = +3;
Δ = b2-4ac
Δ = 142-4·42·3
Δ = -308
Delta is less than zero, so there is no solution for the equation

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