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6x+3=3(3x+1)-3
We move all terms to the left:
6x+3-(3(3x+1)-3)=0
We calculate terms in parentheses: -(3(3x+1)-3), so:We add all the numbers together, and all the variables
3(3x+1)-3
We multiply parentheses
9x+3-3
We add all the numbers together, and all the variables
9x
Back to the equation:
-(9x)
-3x+3=0
We move all terms containing x to the left, all other terms to the right
-3x=-3
x=-3/-3
x=1
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