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6x+3x+2x+x-20=5(x+3)
We move all terms to the left:
6x+3x+2x+x-20-(5(x+3))=0
We add all the numbers together, and all the variables
12x-(5(x+3))-20=0
We calculate terms in parentheses: -(5(x+3)), so:We get rid of parentheses
5(x+3)
We multiply parentheses
5x+15
Back to the equation:
-(5x+15)
12x-5x-15-20=0
We add all the numbers together, and all the variables
7x-35=0
We move all terms containing x to the left, all other terms to the right
7x=35
x=35/7
x=5
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