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6x+3x-5=8x+5(2x-1)
We move all terms to the left:
6x+3x-5-(8x+5(2x-1))=0
We add all the numbers together, and all the variables
9x-(8x+5(2x-1))-5=0
We calculate terms in parentheses: -(8x+5(2x-1)), so:We get rid of parentheses
8x+5(2x-1)
We multiply parentheses
8x+10x-5
We add all the numbers together, and all the variables
18x-5
Back to the equation:
-(18x-5)
9x-18x+5-5=0
We add all the numbers together, and all the variables
-9x=0
x=0/-9
x=0
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