6x+4(2x+3)=40

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Solution for 6x+4(2x+3)=40 equation: 



6x+4(2x+3)=40

We move all terms to the left:

6x+4(2x+3)-(40)=0

We multiply parentheses

6x+8x+12-40=0

We add all the numbers together, and all the variables

14x-28=0

We move all terms containing x to the left, all other terms to the right

14x=28

x=28/14

x=2

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