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6x+4(2x+3-x)=2(5x+6)
We move all terms to the left:
6x+4(2x+3-x)-(2(5x+6))=0
We add all the numbers together, and all the variables
6x+4(x+3)-(2(5x+6))=0
We multiply parentheses
6x+4x-(2(5x+6))+12=0
We calculate terms in parentheses: -(2(5x+6)), so:We add all the numbers together, and all the variables
2(5x+6)
We multiply parentheses
10x+12
Back to the equation:
-(10x+12)
10x-(10x+12)+12=0
We get rid of parentheses
10x-10x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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