6x+4-2(1-x)=10(x+2)-2(x-3)

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Solution for 6x+4-2(1-x)=10(x+2)-2(x-3) equation: 



6x+4-2(1-x)=10(x+2)-2(x-3)

We move all terms to the left:

6x+4-2(1-x)-(10(x+2)-2(x-3))=0

We add all the numbers together, and all the variables

6x-2(-1x+1)-(10(x+2)-2(x-3))+4=0

We multiply parentheses

6x+2x-(10(x+2)-2(x-3))-2+4=0



We calculate terms in parentheses: -(10(x+2)-2(x-3)), so:

10(x+2)-2(x-3)

We multiply parentheses

10x-2x+20+6

We add all the numbers together, and all the variables

8x+26

Back to the equation:

-(8x+26)



We add all the numbers together, and all the variables

8x-(8x+26)+2=0

We get rid of parentheses

8x-8x-26+2=0

We add all the numbers together, and all the variables

-24!=0

There is no solution for this equation

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