6x+4-2(x-7)=6-3x+4(x+8)

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Solution for 6x+4-2(x-7)=6-3x+4(x+8) equation:



6x+4-2(x-7)=6-3x+4(x+8)
We move all terms to the left:
6x+4-2(x-7)-(6-3x+4(x+8))=0
We multiply parentheses
6x-2x-(6-3x+4(x+8))+14+4=0
We calculate terms in parentheses: -(6-3x+4(x+8)), so:
6-3x+4(x+8)
determiningTheFunctionDomain -3x+4(x+8)+6
We multiply parentheses
-3x+4x+32+6
We add all the numbers together, and all the variables
x+38
Back to the equation:
-(x+38)
We add all the numbers together, and all the variables
4x-(x+38)+18=0
We get rid of parentheses
4x-x-38+18=0
We add all the numbers together, and all the variables
3x-20=0
We move all terms containing x to the left, all other terms to the right
3x=20
x=20/3
x=6+2/3

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