6x+4-2(x-7)=6-3x+4(x+8)

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Solution for 6x+4-2(x-7)=6-3x+4(x+8) equation: 



6x+4-2(x-7)=6-3x+4(x+8)

We move all terms to the left:

6x+4-2(x-7)-(6-3x+4(x+8))=0

We multiply parentheses

6x-2x-(6-3x+4(x+8))+14+4=0



We calculate terms in parentheses: -(6-3x+4(x+8)), so:

6-3x+4(x+8)

determiningTheFunctionDomain
-3x+4(x+8)+6

We multiply parentheses

-3x+4x+32+6

We add all the numbers together, and all the variables

x+38

Back to the equation:

-(x+38)



We add all the numbers together, and all the variables

4x-(x+38)+18=0

We get rid of parentheses

4x-x-38+18=0

We add all the numbers together, and all the variables

3x-20=0

We move all terms containing x to the left, all other terms to the right

3x=20

x=20/3

x=6+2/3

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