6x+4=4(2/3x+1)

Solution for 6x+4=4(2/3x+1) equation:

6x+4=4(2/3x+1)

We move all terms to the left:

6x+4-(4(2/3x+1))=0


Domain of the equation: 3x+1))!=0

x∈R


We multiply all the terms by the denominator


6x*3x+4*3x+1))-(4(2+1))=0

We add all the numbers together, and all the variables

6x*3x+4*3x+1))-(43)=0

We add all the numbers together, and all the variables

6x*3x+4*3x=0

Wy multiply elements

18x^2+12x=0

a = 18; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·18·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*18}=\frac{-24}{36}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*18}=\frac{0}{36}
=0
$