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6x+4=4(3/2x+1)
We move all terms to the left:
6x+4-(4(3/2x+1))=0
Domain of the equation: 2x+1))!=0We multiply all the terms by the denominator
x∈R
6x*2x+4*2x+1))-(4(3+1))=0
We add all the numbers together, and all the variables
6x*2x+4*2x+1))-(44)=0
We add all the numbers together, and all the variables
6x*2x+4*2x=0
Wy multiply elements
12x^2+8x=0
a = 12; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·12·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*12}=\frac{-16}{24} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*12}=\frac{0}{24} =0 $
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