6x+4x(2x-20)=263

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Solution for 6x+4x(2x-20)=263 equation:



6x+4x(2x-20)=263
We move all terms to the left:
6x+4x(2x-20)-(263)=0
We multiply parentheses
8x^2+6x-80x-263=0
We add all the numbers together, and all the variables
8x^2-74x-263=0
a = 8; b = -74; c = -263;
Δ = b2-4ac
Δ = -742-4·8·(-263)
Δ = 13892
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{13892}=\sqrt{4*3473}=\sqrt{4}*\sqrt{3473}=2\sqrt{3473}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-74)-2\sqrt{3473}}{2*8}=\frac{74-2\sqrt{3473}}{16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-74)+2\sqrt{3473}}{2*8}=\frac{74+2\sqrt{3473}}{16} $

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