6x+4x(4-x)=48

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Solution for 6x+4x(4-x)=48 equation: 



6x+4x(4-x)=48

We move all terms to the left:

6x+4x(4-x)-(48)=0

We add all the numbers together, and all the variables

6x+4x(-1x+4)-48=0

We multiply parentheses

-4x^2+6x+16x-48=0

We add all the numbers together, and all the variables

-4x^2+22x-48=0

a = -4; b = 22; c = -48;
Δ = b2-4ac
Δ = 222-4·(-4)·(-48)
Δ = -284
Delta is less than zero, so there is no solution for the equation

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