6x+4x+2(x-4)=100

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Solution for 6x+4x+2(x-4)=100 equation: 



6x+4x+2(x-4)=100

We move all terms to the left:

6x+4x+2(x-4)-(100)=0

We add all the numbers together, and all the variables

10x+2(x-4)-100=0

We multiply parentheses

10x+2x-8-100=0

We add all the numbers together, and all the variables

12x-108=0

We move all terms containing x to the left, all other terms to the right

12x=108

x=108/12

x=9

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