6x+4x+7x=3(6x-12)-4(x-6)

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Solution for 6x+4x+7x=3(6x-12)-4(x-6) equation: 



6x+4x+7x=3(6x-12)-4(x-6)

We move all terms to the left:

6x+4x+7x-(3(6x-12)-4(x-6))=0

We add all the numbers together, and all the variables

17x-(3(6x-12)-4(x-6))=0



We calculate terms in parentheses: -(3(6x-12)-4(x-6)), so:

3(6x-12)-4(x-6)

We multiply parentheses

18x-4x-36+24

We add all the numbers together, and all the variables

14x-12

Back to the equation:

-(14x-12)



We get rid of parentheses

17x-14x+12=0

We add all the numbers together, and all the variables

3x+12=0

We move all terms containing x to the left, all other terms to the right

3x=-12

x=-12/3

x=-4

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