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6x+4x-12=2(5x+4)
We move all terms to the left:
6x+4x-12-(2(5x+4))=0
We add all the numbers together, and all the variables
10x-(2(5x+4))-12=0
We calculate terms in parentheses: -(2(5x+4)), so:We get rid of parentheses
2(5x+4)
We multiply parentheses
10x+8
Back to the equation:
-(10x+8)
10x-10x-8-12=0
We add all the numbers together, and all the variables
-20!=0
There is no solution for this equation
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