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6x+4x-6=24/9x
We move all terms to the left:
6x+4x-6-(24/9x)=0
Domain of the equation: 9x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
6x+4x-(+24/9x)-6=0
We add all the numbers together, and all the variables
10x-(+24/9x)-6=0
We get rid of parentheses
10x-24/9x-6=0
We multiply all the terms by the denominator
10x*9x-6*9x-24=0
Wy multiply elements
90x^2-54x-24=0
a = 90; b = -54; c = -24;
Δ = b2-4ac
Δ = -542-4·90·(-24)
Δ = 11556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11556}=\sqrt{36*321}=\sqrt{36}*\sqrt{321}=6\sqrt{321}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-6\sqrt{321}}{2*90}=\frac{54-6\sqrt{321}}{180} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+6\sqrt{321}}{2*90}=\frac{54+6\sqrt{321}}{180} $
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