6x+5(4+2x)=100

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Solution for 6x+5(4+2x)=100 equation: 



6x+5(4+2x)=100

We move all terms to the left:

6x+5(4+2x)-(100)=0

We add all the numbers together, and all the variables

6x+5(2x+4)-100=0

We multiply parentheses

6x+10x+20-100=0

We add all the numbers together, and all the variables

16x-80=0

We move all terms containing x to the left, all other terms to the right

16x=80

x=80/16

x=5

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