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6x+5=1+(3x+2)
We move all terms to the left:
6x+5-(1+(3x+2))=0
We calculate terms in parentheses: -(1+(3x+2)), so:We get rid of parentheses
1+(3x+2)
determiningTheFunctionDomain (3x+2)+1
We get rid of parentheses
3x+2+1
We add all the numbers together, and all the variables
3x+3
Back to the equation:
-(3x+3)
6x-3x-3+5=0
We add all the numbers together, and all the variables
3x+2=0
We move all terms containing x to the left, all other terms to the right
3x=-2
x=-2/3
x=-2/3
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