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6x+5=1+2(3x+2)=
We move all terms to the left:
6x+5-(1+2(3x+2))=0
We calculate terms in parentheses: -(1+2(3x+2)), so:We get rid of parentheses
1+2(3x+2)
determiningTheFunctionDomain 2(3x+2)+1
We multiply parentheses
6x+4+1
We add all the numbers together, and all the variables
6x+5
Back to the equation:
-(6x+5)
6x-6x-5+5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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