6x+5=3(2x+1)6x+5=3(2x+1)

Solution for 6x+5=3(2x+1)6x+5=3(2x+1) equation:

6x+5=3(2x+1)6x+5=3(2x+1)

We move all terms to the left:

6x+5-(3(2x+1)6x+5)=0


We calculate terms in parentheses: -(3(2x+1)6x+5), so:

3(2x+1)6x+5

We multiply parentheses

36x^2+18x+5

Back to the equation:

-(36x^2+18x+5)


We get rid of parentheses

-36x^2+6x-18x-5+5=0

We add all the numbers together, and all the variables

-36x^2-12x=0

a = -36; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·(-36)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*-36}=\frac{0}{-72}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*-36}=\frac{24}{-72}
=-1/3
$