6x+8x-36=3x/5x

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Solution for 6x+8x-36=3x/5x equation:



6x+8x-36=3x/5x
We move all terms to the left:
6x+8x-36-(3x/5x)=0
Domain of the equation: 5x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
6x+8x-(+3x/5x)-36=0
We add all the numbers together, and all the variables
14x-(+3x/5x)-36=0
We get rid of parentheses
14x-3x/5x-36=0
We multiply all the terms by the denominator
14x*5x-3x-36*5x=0
We add all the numbers together, and all the variables
-3x+14x*5x-36*5x=0
Wy multiply elements
70x^2-3x-180x=0
We add all the numbers together, and all the variables
70x^2-183x=0
a = 70; b = -183; c = 0;
Δ = b2-4ac
Δ = -1832-4·70·0
Δ = 33489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{33489}=183$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-183)-183}{2*70}=\frac{0}{140} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-183)+183}{2*70}=\frac{366}{140} =2+43/70 $

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