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6x+9+3x=3(3x+3)
We move all terms to the left:
6x+9+3x-(3(3x+3))=0
We add all the numbers together, and all the variables
9x-(3(3x+3))+9=0
We calculate terms in parentheses: -(3(3x+3)), so:We get rid of parentheses
3(3x+3)
We multiply parentheses
9x+9
Back to the equation:
-(9x+9)
9x-9x-9+9=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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