6x+9/x-3=9

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Solution for 6x+9/x-3=9 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

6*x+9/x-3 = 9 // - 9

6*x+9/x-9-3 = 0

6*x^1+9*x^-1-12*x^0 = 0

(6*x^2-12*x^1+9*x^0)/(x^1) = 0 // * x^2

x^1*(6*x^2-12*x^1+9*x^0) = 0

x^1

6*x^2-12*x+9 = 0

6*x^2-12*x+9 = 0

DELTA = (-12)^2-(4*6*9)

DELTA = -72

DELTA < 0

x in { }

x belongs to the empty set

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