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6x+9x+5=(2x+3)(3x+2)
We move all terms to the left:
6x+9x+5-((2x+3)(3x+2))=0
We add all the numbers together, and all the variables
15x-((2x+3)(3x+2))+5=0
We multiply parentheses ..
-((+6x^2+4x+9x+6))+15x+5=0
We calculate terms in parentheses: -((+6x^2+4x+9x+6)), so:We add all the numbers together, and all the variables
(+6x^2+4x+9x+6)
We get rid of parentheses
6x^2+4x+9x+6
We add all the numbers together, and all the variables
6x^2+13x+6
Back to the equation:
-(6x^2+13x+6)
15x-(6x^2+13x+6)+5=0
We get rid of parentheses
-6x^2+15x-13x-6+5=0
We add all the numbers together, and all the variables
-6x^2+2x-1=0
a = -6; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·(-6)·(-1)
Δ = -20
Delta is less than zero, so there is no solution for the equation
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