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6x+9x+5=(2x+3)(3x+2)x2
We move all terms to the left:
6x+9x+5-((2x+3)(3x+2)x2)=0
We add all the numbers together, and all the variables
15x-((2x+3)(3x+2)x2)+5=0
We multiply parentheses ..
-((+6x^2+4x+9x+6)x2)+15x+5=0
We calculate terms in parentheses: -((+6x^2+4x+9x+6)x2), so:
(+6x^2+4x+9x+6)x2
We multiply parentheses
6x^4+4x^3+9x^3+6x^2
We do not support expression: x^4
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