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6x-(2x+3(x-1))=x+20
We move all terms to the left:
6x-(2x+3(x-1))-(x+20)=0
We get rid of parentheses
6x-(2x+3(x-1))-x-20=0
We calculate terms in parentheses: -(2x+3(x-1)), so:We add all the numbers together, and all the variables
2x+3(x-1)
We multiply parentheses
2x+3x-3
We add all the numbers together, and all the variables
5x-3
Back to the equation:
-(5x-3)
5x-(5x-3)-20=0
We get rid of parentheses
5x-5x+3-20=0
We add all the numbers together, and all the variables
-17!=0
There is no solution for this equation
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