6x-(2x+5)=2+(3x+)5

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Solution for 6x-(2x+5)=2+(3x+)5 equation: 



6x-(2x+5)=2+(3x+)5

We move all terms to the left:

6x-(2x+5)-(2+(3x+)5)=0

We add all the numbers together, and all the variables

6x-(2x+5)-(2+(+3x)5)=0

We get rid of parentheses

6x-2x-(2+(+3x)5)-5=0



We calculate terms in parentheses: -(2+(+3x)5), so:

2+(+3x)5

determiningTheFunctionDomain
(+3x)5+2

We multiply parentheses

15x+2

Back to the equation:

-(15x+2)



We add all the numbers together, and all the variables

4x-(15x+2)-5=0

We get rid of parentheses

4x-15x-2-5=0

We add all the numbers together, and all the variables

-11x-7=0

We move all terms containing x to the left, all other terms to the right

-11x=7

x=7/-11

x=-7/11

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