6x-(2x-3(x+1))=-x+20

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Solution for 6x-(2x-3(x+1))=-x+20 equation: 



6x-(2x-3(x+1))=-x+20

We move all terms to the left:

6x-(2x-3(x+1))-(-x+20)=0

We add all the numbers together, and all the variables

6x-(2x-3(x+1))-(-1x+20)=0

We get rid of parentheses

6x-(2x-3(x+1))+1x-20=0



We calculate terms in parentheses: -(2x-3(x+1)), so:

2x-3(x+1)

We multiply parentheses

2x-3x-3

We add all the numbers together, and all the variables

-1x-3

Back to the equation:

-(-1x-3)



We add all the numbers together, and all the variables

7x-(-1x-3)-20=0

We get rid of parentheses

7x+1x+3-20=0

We add all the numbers together, and all the variables

8x-17=0

We move all terms containing x to the left, all other terms to the right

8x=17

x=17/8

x=2+1/8

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