6x-(3x+2)+x-1=3x+(2x-1)+5

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Solution for 6x-(3x+2)+x-1=3x+(2x-1)+5 equation: 



6x-(3x+2)+x-1=3x+(2x-1)+5

We move all terms to the left:

6x-(3x+2)+x-1-(3x+(2x-1)+5)=0

We add all the numbers together, and all the variables

7x-(3x+2)-(3x+(2x-1)+5)-1=0

We get rid of parentheses

7x-3x-(3x+(2x-1)+5)-2-1=0



We calculate terms in parentheses: -(3x+(2x-1)+5), so:

3x+(2x-1)+5

We get rid of parentheses

3x+2x-1+5

We add all the numbers together, and all the variables

5x+4

Back to the equation:

-(5x+4)



We add all the numbers together, and all the variables

4x-(5x+4)-3=0

We get rid of parentheses

4x-5x-4-3=0

We add all the numbers together, and all the variables

-1x-7=0

We move all terms containing x to the left, all other terms to the right

-x=7

x=7/-1

x=-7

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