6x-(3x-12)=14+7x-4(x+10)

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Solution for 6x-(3x-12)=14+7x-4(x+10) equation: 



6x-(3x-12)=14+7x-4(x+10)

We move all terms to the left:

6x-(3x-12)-(14+7x-4(x+10))=0

We get rid of parentheses

6x-3x-(14+7x-4(x+10))+12=0



We calculate terms in parentheses: -(14+7x-4(x+10)), so:

14+7x-4(x+10)

determiningTheFunctionDomain
7x-4(x+10)+14

We multiply parentheses

7x-4x-40+14

We add all the numbers together, and all the variables

3x-26

Back to the equation:

-(3x-26)



We add all the numbers together, and all the variables

3x-(3x-26)+12=0

We get rid of parentheses

3x-3x+26+12=0

We add all the numbers together, and all the variables

38!=0

There is no solution for this equation

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