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6x-(5x+5)=-8-2-(x+12)
We move all terms to the left:
6x-(5x+5)-(-8-2-(x+12))=0
We get rid of parentheses
6x-5x-(-8-2-(x+12))-5=0
We calculate terms in parentheses: -(-8-2-(x+12)), so:We add all the numbers together, and all the variables
-8-2-(x+12)
determiningTheFunctionDomain -(x+12)-8-2
We add all the numbers together, and all the variables
-(x+12)-10
We get rid of parentheses
-x-12-10
We add all the numbers together, and all the variables
-1x-22
Back to the equation:
-(-1x-22)
x-(-1x-22)-5=0
We get rid of parentheses
x+1x+22-5=0
We add all the numbers together, and all the variables
2x+17=0
We move all terms containing x to the left, all other terms to the right
2x=-17
x=-17/2
x=-8+1/2
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