6x-(x+3)=2(x+4)+x

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Solution for 6x-(x+3)=2(x+4)+x equation: 



6x-(x+3)=2(x+4)+x

We move all terms to the left:

6x-(x+3)-(2(x+4)+x)=0

We get rid of parentheses

6x-x-(2(x+4)+x)-3=0



We calculate terms in parentheses: -(2(x+4)+x), so:

2(x+4)+x

We add all the numbers together, and all the variables

x+2(x+4)

We multiply parentheses

x+2x+8

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We add all the numbers together, and all the variables

5x-(3x+8)-3=0

We get rid of parentheses

5x-3x-8-3=0

We add all the numbers together, and all the variables

2x-11=0

We move all terms containing x to the left, all other terms to the right

2x=11

x=11/2

x=5+1/2

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