6x-(x-12)=4x-(x-28)

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Solution for 6x-(x-12)=4x-(x-28) equation: 



6x-(x-12)=4x-(x-28)

We move all terms to the left:

6x-(x-12)-(4x-(x-28))=0

We get rid of parentheses

6x-x-(4x-(x-28))+12=0



We calculate terms in parentheses: -(4x-(x-28)), so:

4x-(x-28)

We get rid of parentheses

4x-x+28

We add all the numbers together, and all the variables

3x+28

Back to the equation:

-(3x+28)



We add all the numbers together, and all the variables

5x-(3x+28)+12=0

We get rid of parentheses

5x-3x-28+12=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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