6x-(x-4)=2(x+3)

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Solution for 6x-(x-4)=2(x+3) equation:



6x-(x-4)=2(x+3)
We move all terms to the left:
6x-(x-4)-(2(x+3))=0
We get rid of parentheses
6x-x-(2(x+3))+4=0
We calculate terms in parentheses: -(2(x+3)), so:
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
We add all the numbers together, and all the variables
5x-(2x+6)+4=0
We get rid of parentheses
5x-2x-6+4=0
We add all the numbers together, and all the variables
3x-2=0
We move all terms containing x to the left, all other terms to the right
3x=2
x=2/3
x=2/3

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