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6x-+(3x+12)=9
We move all terms to the left:
6x-+(3x+12)-(9)=0
determiningTheFunctionDomain 6x+(3x+12)-9-=0
We add all the numbers together, and all the variables
6x+(3x+12)=0
We get rid of parentheses
6x+3x+12=0
We add all the numbers together, and all the variables
9x+12=0
We move all terms containing x to the left, all other terms to the right
9x=-12
x=-12/9
x=-1+1/3
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