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6x-1-(x+3)=3(4x+1)
We move all terms to the left:
6x-1-(x+3)-(3(4x+1))=0
We get rid of parentheses
6x-x-(3(4x+1))-3-1=0
We calculate terms in parentheses: -(3(4x+1)), so:We add all the numbers together, and all the variables
3(4x+1)
We multiply parentheses
12x+3
Back to the equation:
-(12x+3)
5x-(12x+3)-4=0
We get rid of parentheses
5x-12x-3-4=0
We add all the numbers together, and all the variables
-7x-7=0
We move all terms containing x to the left, all other terms to the right
-7x=7
x=7/-7
x=-1
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