6x-1/2(2x-3)=3(1-x)-7/6(x+2)

Solution for 6x-1/2(2x-3)=3(1-x)-7/6(x+2) equation:

6x-1/2(2x-3)=3(1-x)-7/6(x+2)

We move all terms to the left:

6x-1/2(2x-3)-(3(1-x)-7/6(x+2))=0


Domain of the equation: 2(2x-3)!=0

x∈R



Domain of the equation: 6(x+2))!=0

x∈R


We add all the numbers together, and all the variables

6x-1/2(2x-3)-(3(-1x+1)-7/6(x+2))=0

We calculate fractions


6x+(-6xx/(2(2x-3)*6(x+2)))+(-(-3x-14x2)/(2(2x-3)*6(x+2)))=0


We calculate terms in parentheses: +(-6xx/(2(2x-3)*6(x+2))), so:

-6xx/(2(2x-3)*6(x+2))

We multiply all the terms by the denominator


-6xx

Back to the equation:

+(-6xx)



We calculate terms in parentheses: +(-(-3x-14x2)/(2(2x-3)*6(x+2))), so:

-(-3x-14x2)/(2(2x-3)*6(x+2))

We add all the numbers together, and all the variables

-(-3x-14x^2)/(2(2x-3)*6(x+2))

We multiply all the terms by the denominator


-(-3x-14x^2)

We get rid of parentheses

14x^2+3x

Back to the equation:

+(14x^2+3x)


We get rid of parentheses

14x^2+6x-6xx+3x=0

We add all the numbers together, and all the variables

14x^2+9x-6xx=0