6x-10+8x=5(4x-3)+2

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Solution for 6x-10+8x=5(4x-3)+2 equation: 



6x-10+8x=5(4x-3)+2

We move all terms to the left:

6x-10+8x-(5(4x-3)+2)=0

We add all the numbers together, and all the variables

14x-(5(4x-3)+2)-10=0



We calculate terms in parentheses: -(5(4x-3)+2), so:

5(4x-3)+2

We multiply parentheses

20x-15+2

We add all the numbers together, and all the variables

20x-13

Back to the equation:

-(20x-13)



We get rid of parentheses

14x-20x+13-10=0

We add all the numbers together, and all the variables

-6x+3=0

We move all terms containing x to the left, all other terms to the right

-6x=-3

x=-3/-6

x=1/2

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