6x-10=2(x-1)+4(x-2)

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Solution for 6x-10=2(x-1)+4(x-2) equation: 



6x-10=2(x-1)+4(x-2)

We move all terms to the left:

6x-10-(2(x-1)+4(x-2))=0



We calculate terms in parentheses: -(2(x-1)+4(x-2)), so:

2(x-1)+4(x-2)

We multiply parentheses

2x+4x-2-8

We add all the numbers together, and all the variables

6x-10

Back to the equation:

-(6x-10)



We get rid of parentheses

6x-6x+10-10=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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