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6x-11=3(3x+10)+1
We move all terms to the left:
6x-11-(3(3x+10)+1)=0
We calculate terms in parentheses: -(3(3x+10)+1), so:We get rid of parentheses
3(3x+10)+1
We multiply parentheses
9x+30+1
We add all the numbers together, and all the variables
9x+31
Back to the equation:
-(9x+31)
6x-9x-31-11=0
We add all the numbers together, and all the variables
-3x-42=0
We move all terms containing x to the left, all other terms to the right
-3x=42
x=42/-3
x=-14
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